(3)/(x^2-2x)-(2)/(x)=(8)/(x-2)

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Solution for (3)/(x^2-2x)-(2)/(x)=(8)/(x-2) equation: 


D( x )

x^2-(2*x) = 0

x-2 = 0

x = 0

x^2-(2*x) = 0

x^2-(2*x) = 0

x^2-2*x = 0

x^2-2*x = 0

DELTA = (-2)^2-(0*1*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+2)/(1*2) or x = (2-4^(1/2))/(1*2)

x = 2 or x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

3/(x^2-(2*x))-(2/x) = 8/(x-2) // - 8/(x-2)

3/(x^2-(2*x))-(8/(x-2))-(2/x) = 0

3/(x^2-2*x)-8*(x-2)^-1-2*x^-1 = 0

3/(x^2-2*x)-8/(x-2)-2/x = 0

x^2-2*x = 0

x^2-2*x = 0

x*(x-2) = 0

x-2 = 0 // + 2

x = 2

x*(x-2) = 0

3/(x*(x-2))-8/(x-2)-2/x = 0

3/(x*(x-2))+(-8*x)/(x*(x-2))+(-2*(x-2))/(x*(x-2)) = 0

3-2*(x-2)-8*x = 0

3-8*x-2*x+4 = 0

7-10*x = 0

(7-10*x)/(x*(x-2)) = 0

(7-10*x)/(x*(x-2)) = 0 // * x*(x-2)

7-10*x = 0

7-10*x = 0 // - 7

-10*x = -7 // : -10

x = -7/(-10)

x = 7/10

x = 7/10

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